| Jsp&Servelet 学习笔记(1) |
|
作者：佚名 文章来源：www.top-sales.com.cn 点击数： 更新时间：2007-3-22  |
| [ 字体：缩小 正常 放大 | 双击自动滚屏 ] |
请选择合适的字体颜色：
|
|
out.println("<title>Help Page</title></head><body>");
out.println("<h2>Please submit your information</h2>");
//make sure method="post" so that the servlet service method
//calls doPost in the response to this form submit
out.println( "<form method="post" action ="" + request.getContextPath( ) + "/firstservlet" >");
out.println("<table border="0"><tr><td valign="top">");
out.println("Your first name: </td> <td valign="top">");
out.println("<input type="text" name="firstname" size="20">");
out.println("</td></tr><tr><td valign="top">");
out.println("Your last name: </td> <td valign="top">");
out.println("<input type="text" name="lastname" size="20">");
out.println("</td></tr><tr><td valign="top">");
out.println("Your email: </td> <td valign="top">");
out.println("<input type="text" name="email" size="20">");
out.println("</td></tr><tr><td valign="top">");
out.println("<input type="submit" value="Submit Info"></td></tr>");
out.println("</table></form>"); out.println("</body></html>");
}
//doGet
public void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, java.io.IOException ...{
//display the parameter names and values
Enumeration paramNames = request.getParameterNames( );
String parName;
//this will hold the name of the parameter 上一页 [1] [2] [3] [4] 下一页
|
|
|
| 文章录入：admin 责任编辑：admin |
上一个文章： Jsp&Servelet 学习笔记(2)
下一个文章： Jsp基础知识总结 |
| 【发表评论】【加入收藏】【告诉好友】【打印此文】【关闭窗口】 |
